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posted by on Tuesday May 16 2017, @10:52AM   Printer-friendly
from the not-the-end-of-secrecy dept.

Math is hard. Indeed, much of the modern infrastructure for secure communication depends heavily on the difficulty of elementary mathematics — of factoring, to be exact. It's easy to reduce a small number like 15 to its prime factors (3 x 5), but factoring numbers with a few hundred digits is still exceedingly difficult. For this reason, the RSA cryptosystem, an encryption scheme that derives its security from the difficulty of integer factorization, remains a popular tool for secure communication.

Research suggests, however, that a quantum computer would be able to factor a large number far more quickly than the best available methods today. If researchers could build a quantum computer that could outperform classical supercomputers, the thinking goes, cryptographers could use a particular algorithm called Shor's algorithm to render the RSA cryptosystem unsalvageable. The deadline to avert this may arrive sooner than we think: Google recently claimed that its quantum computers will be able to perform a calculation that's beyond the reach of any classical computer by the end of the year. In light of this, cryptographers are scrambling to find a new quantum-proof security standard.

Yet perhaps RSA isn't in as much trouble as researchers have assumed. A few weeks ago, a paper surfaced on the Cryptology ePrint Archive that asked: "Is it actually true that quantum computers will kill RSA?" The authors note that even though a quantum computer running Shor's algorithm would be faster than a classical computer, the RSA algorithm is faster than both. And the larger the RSA "key" — the number that must be factored — the greater the speed difference.

-- submitted from IRC


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  • (Score: 0) by Anonymous Coward on Tuesday May 16 2017, @02:21PM (1 child)

    by Anonymous Coward on Tuesday May 16 2017, @02:21PM (#510534)

    For this reason, the RSA cryptosystem, an encryption scheme that derives its security from the difficulty of integer factorization ...

    Not exactly. It remains an open problem whether or not RSA's security actually depends on the difficulty of integer factorization.

    The security of RSA encryption depends on the difficulty of the so-called RSA Problem [wikipedia.org]: Given integers C, N, e, (plus a bunch of extra constraints) compute P where C ≡ Pe (mod N).

    Factoring N is the most efficient currently-known method to solve the RSA problem. But there is no proof that the RSA problem is necessarily as hard as factoring N: it is possible that breaking RSA could actually be easier than factoring N.

  • (Score: 0, Touché) by Anonymous Coward on Tuesday May 16 2017, @02:26PM

    by Anonymous Coward on Tuesday May 16 2017, @02:26PM (#510537)

    Prove it.