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posted by martyb on Wednesday March 16 2016, @12:43PM   Printer-friendly
from the 7000-picometers dept.

ARM Holdings and Taiwan Semiconductor Manufacturing Company (TSMC) have announced a collaboration on 7nm chips. They have already worked together to create CPUs at the 16nm and 10nm process nodes. There is no indication that extreme ultraviolet lithography (EUV) will be used for 7nm chips, whereas IBM used the technology for its 7nm demonstration chip last year:

IBM was the first to announce the creation of a 7nm chip, although the innovative processes it used to create it also meant that mass production wouldn't be possible for a few more years, due to the high cost. Chances are that IBM's 7nm chips could arrive sometime in 2018, or in 2019 at the latest.

Intel has already delayed its 10nm chip production to the second half of 2017, which means its 7nm chips won't arrive until late 2019, or even early 2020. That gives IBM and other companies the opportunity to surpass Intel in cutting-edge process technology for the first time.

It's not clear when TSMC will be mass-producing 7nm chips. However, knowing that its 10nm chips are likely to appear early next year, then chances are that its 7nm chips will be ready sometime in 2019, potentially surpassing Intel with quicker production of 7nm chips, too.

Also at The Register .


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  • (Score: 0) by Anonymous Coward on Wednesday March 16 2016, @10:10PM

    by Anonymous Coward on Wednesday March 16 2016, @10:10PM (#319260)

    Given that a short only has 16 bits,

    Technically, all you're really guaranteed is that a short has at least as many bits as a char and no more than an int.

  • (Score: 0) by Anonymous Coward on Wednesday March 16 2016, @10:20PM

    by Anonymous Coward on Wednesday March 16 2016, @10:20PM (#319267)

    Technically, all you're really guaranteed is that a short has at least as many bits as a char and no more than an int.

    Not quite; C also guarantees that a (signed) short can store values between -32767 and +32767 (inclusive), which implies that it has at least 15 value bits (plus one sign bit).